7d^2+9d+2=0

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Solution for 7d^2+9d+2=0 equation: 



7d^2+9d+2=0

a = 7; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·7·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*7}=\frac{-14}{14}
=-1
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*7}=\frac{-4}{14}
=-2/7
$

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